Fermat’s Last Theorem

Fermat’s Last Theorem states that:

There are no positive integers x, y, and z  with x^n + y^n = z^n if n is an integer greater than 2.

For n = 2 there are many solutions:

( 3, 4, 5) ( 5, 12, 13) ( 7, 24, 25) ( 8, 15, 17)
( 9, 40, 41) (11, 60, 61) (12, 35, 37) (13, 84, 85)
(16, 63, 65) (20, 21, 29) (28, 45, 53) (33, 56, 65)
(36, 77, 85) (39, 80, 89) (48, 55, 73) (65, 72, 97) … the Pythagorean triples.

In the margin of his copy of the Arithmetica of Diophantus the French jurist Fermat wrote circa 1637 that for greater n no such triples can be found; he added that he had a marvelous proof for this, which however the margin was too small to contain:

Cubum autem in duos cubos, aut quadrato-quadratum in duos quadrato-quadratos, et generaliter nullam in infinitum ultra quadratum potestatum in duos ejusdem nominis fas est dividere; cujus rei demonstrationem mirabilem sane detexi. Hanc marginis exiguitas non caparet.

Some of the greatest mathematical minds in history have applied their genius to this problem, none succeeded. Every other result which Fermat had announced in like manner had long ago been dealt with; only this one, the last, remained. Finally, 358 years after Fermat wrote his theorem, Andrew Wiles saw an application of elliptic curves and modular forms (20th century mathematical constructs, not known to earlier mathematicians) that could contribute to the proof.


Let n, a, b, c, \in \mathbb{Z} with n > 2.
If a^n + b^n  = c^n then abc  = 0.


The proof follows a program formulated around 1985 by Frey and Serre[F,S]. By classical results of Fermat, Euler, Dirichlet, Legendre, and Lamé, we may assume that n = p, an odd prime ≥ 11. Suppose a, b, c  \in \mathbb{Z} , abc \neq 0, and a^p + b^p  = c^p. Without loss of generality we may assume that 2|a and b \equiv 1 \bmod 4. Frey [F] observed that the elliptic curve E : y^2 = x(x -a^p )(x + b^p) has the following ‘remarkable’ properties:
(1) E is semistable with conductor N_E = \prod_{{l}|abc} {l} ; and
(2) \overline{\rho}_{E,p} is unramified outside 2p and is flat at p .
By the modularity theorem of Wiles and Taylor-Wiles [W,T-W], there is an eigenform f \in S_2 (\Gamma_0(N_E)) such that \rho_{f,p} = \rho_{E,p}. A theorem of Mazur implies that E,p is irreducible, so Ribet’s theorem [R] produces a Hecke eigenform g \in S_2 (\Gamma_0(2)) such that \rho_{g,p} \equiv \rho_{f,p} \bmod {\tt p} for some {\tt p}|p. But X_0(2) has genus zero, so S_2 (\Gamma_0(2)) = 0 . This is a contradiction and Fermat’s Last Theorem follows. Q.E.D.


[F] Frey, G.: Links between semistable elliptic curves and certain Diophantine equations. Ann. Univ. Sarav. 1 (1986), 1-40.
[R] Ribet, K.: On modular representations of Gal(\overline{\mathbb{Q}}/\mathbb{Q}) arising from modular forms. Invent. Math. 100 (1990), 431-476.
[S] Serre, J.-P.: Sur les représentations modulaires de degré 2 de Gal(\overline{\mathbb{Q}}/\mathbb{Q}) . Duke Math. J. 54 (1987), 179-230.
[T-W] Taylor, R. L., Wiles, A.: Ring-theoretic properties of certain Hecke algebras. Annals of Math. 141 (1995), 553-572.
[W] Wiles, A.: Modular elliptic curves and Fermat’s Last Theorem. Annals of Math. 141 (1995), 443-551.

It doesn’t fit the margin,
But it does go on a shirt.

Genealogy of a Theorem:



~300 BC Euclid of Alexandria
~250 AD Diophantus of Alexandria
1601-1665 Pierre de Fermat
1707-1783 Leonhard Euler
1736-1813 Joseph Louis Lagrange
1776-1831 Sophie Germain
1777-1855 Carl Friedrich Gauss
1789-1857 Augustin Louis Cauchy
1795-1870 Gabriel Lamé
1805-1870 Peter Gustav Lejeune Dirichlet
1809-1882 Joseph Liouville
1810-1893 Ernst Eduard Kummer
1882-1973 Harry Schultz Vandiver
Gerhard Frey
Kenneth A. Ribet
Andrew J. Wiles

(hat-tips: van der Poorten; Darmon and Levesque)


Leave a Reply

Fill in your details below or click an icon to log in:

WordPress.com Logo

You are commenting using your WordPress.com account. Log Out /  Change )

Google+ photo

You are commenting using your Google+ account. Log Out /  Change )

Twitter picture

You are commenting using your Twitter account. Log Out /  Change )

Facebook photo

You are commenting using your Facebook account. Log Out /  Change )


Connecting to %s